Students, who look for help with their algebra homework or classwork, usually think of getting extra coaching from faculty or studying with a classmate who knows the subject really well. While both methods can help you get by, they’re not always effective.

**Online tutoring**has grown popular over the past few years as more and more students turn to the internet for help and information. Taking education online is an effective way to incorporate learning into their schedules. Online tutoring is reliable, safe and quick. You’ll also find that there are a plethora of sites and services to choose from. At its most basic, there are sites which have a**free online calculator**that you can input your problem into and it gives you an answer instantly.## Help For Algebra 2

## Solved Examples

**Question 1:**Solve for x, 7x + 16 = 3x + 5

**Solution:**

Given, 7x + 16 = 3x + 5

Subtract 3x from both sides of the equation,

=> 7x - 3x + 16 = 3x - 3x + 5

=> 4x + 16 = 5

Subtract 16 from both sides of the equation,

=> 4x + 16 - 16 = 5 - 16

=> 4x = - 11

Divide both side by 4,

=> $\frac{4x}{4} = \frac{-11}{4}$

=> x = $\frac{-11}{4}$, is the solution.

Subtract 3x from both sides of the equation,

=> 7x - 3x + 16 = 3x - 3x + 5

=> 4x + 16 = 5

Subtract 16 from both sides of the equation,

=> 4x + 16 - 16 = 5 - 16

=> 4x = - 11

Divide both side by 4,

=> $\frac{4x}{4} = \frac{-11}{4}$

=> x = $\frac{-11}{4}$, is the solution.

**Question 2:**Find the value of x, for all whole numbers.

7x - 3 $\leqslant$ 11

**Solution:**

Given,

7x - 3 $\leqslant$ 11

Add 3 from both sides of the equations,

=> 7x - 3 + 3 $\leqslant$ 11 + 3

=> 7x $\leqslant$ 14

Divide both side by 7,

=> $\frac{7x}{7}$ $\leqslant$ $\frac{14}{7}$

=> x $\leqslant$ 2

=>

7x - 3 $\leqslant$ 11

Add 3 from both sides of the equations,

=> 7x - 3 + 3 $\leqslant$ 11 + 3

=> 7x $\leqslant$ 14

Divide both side by 7,

=> $\frac{7x}{7}$ $\leqslant$ $\frac{14}{7}$

=> x $\leqslant$ 2

=>

**Values of x are 0, 1 and 2.**