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Given, 7x + 16 = 3x + 5

Subtract 3x from both sides of the equation,

=> 7x - 3x + 16 = 3x - 3x + 5

=> 4x + 16 = 5

Subtract 16 from both sides of the equation,

=> 4x + 16 - 16 = 5 - 16

=> 4x = - 11

Divide both side by 4,

=> $\frac{4x}{4} = \frac{-11}{4}$

=> x = $\frac{-11}{4}$, is the solution.

Subtract 3x from both sides of the equation,

=> 7x - 3x + 16 = 3x - 3x + 5

=> 4x + 16 = 5

Subtract 16 from both sides of the equation,

=> 4x + 16 - 16 = 5 - 16

=> 4x = - 11

Divide both side by 4,

=> $\frac{4x}{4} = \frac{-11}{4}$

=> x = $\frac{-11}{4}$, is the solution.

7x - 3 $\leqslant$ 11

Given,

7x - 3 $\leqslant$ 11

Add 3 from both sides of the equations,

=> 7x - 3 + 3 $\leqslant$ 11 + 3

=> 7x $\leqslant$ 14

Divide both side by 7,

=> $\frac{7x}{7}$ $\leqslant$ $\frac{14}{7}$

=> x $\leqslant$ 2

=>**Values of x are 0, 1 and 2.**

7x - 3 $\leqslant$ 11

Add 3 from both sides of the equations,

=> 7x - 3 + 3 $\leqslant$ 11 + 3

=> 7x $\leqslant$ 14

Divide both side by 7,

=> $\frac{7x}{7}$ $\leqslant$ $\frac{14}{7}$

=> x $\leqslant$ 2

=>